IfФ=30 degrees,find cos2Ф,1-tan^2Ф/1+tan^2Ф and write cos2Ф in terms of tan.I want answer immediately
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1)cos2Ф=cos60=1/2
2)1-tan²30/1+tan30
=(1-1/3)/(1+1/3)
=2/3*3/4
=1/2
3)R.H.S=1-tan²2Ф/1+tan²2Ф
BYE PYTHAGORAS IDENTITY.....1+tan²α=sec²α=1/cos²α
R.H.S=1-tan²2Ф/(1/cos²2Ф)
=COS²2Ф-SIN²2Ф
=cos2Ф....proved
(NOTE:-In ans(3),i have skipped some steps...try to understand them...if not,tell me i will tell u again)
2)1-tan²30/1+tan30
=(1-1/3)/(1+1/3)
=2/3*3/4
=1/2
3)R.H.S=1-tan²2Ф/1+tan²2Ф
BYE PYTHAGORAS IDENTITY.....1+tan²α=sec²α=1/cos²α
R.H.S=1-tan²2Ф/(1/cos²2Ф)
=COS²2Ф-SIN²2Ф
=cos2Ф....proved
(NOTE:-In ans(3),i have skipped some steps...try to understand them...if not,tell me i will tell u again)
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