Question

If 30 men complete 1/7 the work in 2 days. How many more men should join in now, if the work
has to be completed in 10 more days?​

Answer 1

Answer:

ANS : 6

Step-by-step explanation:

Given, M1 = 30

M2 = 30 + x

W1 = 1/7

W2 = 1 - 1/7 =6/7

D1 =2 and D2 = 10

According to the formula, M1D1W2 = M2D2W1

30×2×(6/7) = (30+x)×10×(1/7)

⇒ 360 = 300 + 10x

⇒ 10x = 360-300

⇒ x = 60/10

⇒ x= 6

Answer 2

6 more men are required to complete the work in next 10 days.

Given,

30 Men complete 1/7 of work in 2 days

To Find,

Number of more men require to complete the work in 10 more days

Solution,

Amount of work left to do = 1 - 1/7

Amount of work left to do = 6/7

Now, let the number of more men needed to be 'x'

$\frac{Number of men * Number of days}{Work done}$ = Constant

Therefore, the above formula would be equal for both the cases

Case 1 -

Number of men  = 30

Number of days = 2

Work done = 1/7

Case 2 -

Number of men  = 30 + x

Number of days = 10

Work done = 6/7

$\frac{30*2}{\frac{1}{7} } = \frac{(30+x)*10}{\frac{6}{7} }$

30 * 2 * 7 = $\frac{(30+x)*10 * 7}{6}$

30 * 2 * 6 = (30 + x) * 10

360 = 300 + 10x

10x = 60

x = 6

Therefore, 6 more men are required.

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