Question

if 30 oxen can plough 1/7th of a field in 2 days how many days 18 oxen will take to do the remaining work ?​

Answer 1

hai guys,

we will use work equivalence method ,

30/18 =(1/7)/(6/7)×x/2

5/3=(1/6)×x/2

×=60/3

=20 days

Answer 2

18 oxen will take 20 days to complete remaining work.

Step-by-step explanation:

Since we have given that

Number of oxen = 30

Number of days = 2

Part of field plough = $\dfrac{1}{7}$

If the number of oxen = 18

Remaining part of field = $1-\dfrac{1}{7}=\dfrac{7-1}{7}=\dfrac{6}{7}$

So, it becomes,

$\dfrac{30\times 2}{\dfrac{1}{7}}=\dfrac{18\times x}{\dfrac{6}{7}}\\\\\dfrac{60}{1}=\dfrac{18x}{6}\\\\60=3x\\\\x=\dfrac{60}{3}\\\\x=20$

Hence, 18 oxen will take 20 days to complete remaining work.

# learn  more:

If 15 oxen or 20 cows can eat the grass of a field in 80 days, then in how many days will 6 oxen and 2 cows eat the same grass?

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