If 300 mL of gas weighs 0.368 at STP, molar mass of gas is
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Given:
P=1 atmp
Volume=300ml=0.300L
T=273K
R=gas constant=0.0821 lit.atm/mol.k
Formula To be used:
By Ideal Gas equation:
PV=nRT
n=PV/RT
n=(1*0.300)/(0.0821)*273
=13.4mmolMW
=368mg/13.4mmol
=27.5mg/mmol=27.5g/mol
Hence molar mass of gas is 27.5g/mol
P=1 atmp
Volume=300ml=0.300L
T=273K
R=gas constant=0.0821 lit.atm/mol.k
Formula To be used:
By Ideal Gas equation:
PV=nRT
n=PV/RT
n=(1*0.300)/(0.0821)*273
=13.4mmolMW
=368mg/13.4mmol
=27.5mg/mmol=27.5g/mol
Hence molar mass of gas is 27.5g/mol
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