If 300 mL of M/20 H2SO4 (aq) solution is diluted to 3 litre. Calculated the molarity after dilution.
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Let M1(molarity H2SO4)=2M, V1(volume of H2SO4)=20ml=0.02L, V2(volume of solution)=1L and M2(molarity of resulting solution)=?
Therefore, M1×V1=M2×V2
M2=0.04M
Normality=M2×n , here n is number of H+ ions an acid can donate
Normality=0.04×2=0.08N
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