Question

If 30°c water is mixed with 50 degree water the resultant degree will be​

Answer 1

Answer:

The obtained water would be slighly lesser than 40 degrees

Answer 2

Given

temprature of water = 30°

water mixed with another water which is at = 50°

Find

resultant temprature of water

Solution

$let \: the \: temprature \:exceed \\ be \: f \\ according \: to \: question \\ f + 30 = 50 - f \\2 f = 20 \\ \\ \\ f = 10 \\ so \: final \: temprature \: = 30 + 10 = 40degree$