Question

if 300m town make a angle of elevation at a point on ground with 300m away from its foot then find the angle of elevation

Answer 1

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Answer 2

Given :

300m town make a angle of elevation at a point on ground with 300m away from its foot

To Find:

find the angle of elevation

Solution:

Height of town = Perpendicular = 300 m

It makes an angle of elevation at a point on ground with 300m away from its foot

So, Base = 300 m

To find Angle of elevation:

$Tan \theta = \frac{Perpendicular}{Base}\\Tan \theta = \frac{300}{300}\\Tan \theta = 1\\\theta = tan^{-1}(1)\\\theta =45^{\circ}$

Hence the angle of elevation is 45°