If 309 J of heat are removed from 10.0 g of ice (specific heat = 2.06 J/g
ºC) at -5.5 ºC, what is the final temperature of the ice sample?
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Answer:
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ºᴄ) ᴀᴛ -. ºᴄ,
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Answer:
= (36.0 g) (90.0 °C) (4.184 J g¯1 °C¯1) = 13,556 J = 13.556 kJ
q = (40.7 kJ/mol) (36.0 g / 18.0 g/mol) = 81.4 kJ
q = (36.0 g) (100.0 °C) (2.02 J g¯1 °C¯1) = 7272 J = 7.272 kJ
q = 102 kJ (rounded to the appropriate number of significant figures)
Explanation:
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