If θ=30O, verify that cos3θ=4cos2θ-3cosθ
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Answer:
ok
so the answer is 1=1
Step-by-step explanation:
a) cos(3×30°)=4cos^3(30°)-3cos(30°)
cos 90°=4cos^3(30°)-3cos(30°)
0=4(_/3÷2)^3-3×_/3÷2
0=(12_/3)/8-(3_/3)/2
0=(3_/3)/2-(3_/3)/2
0=0
b) sin(3×30°)=3sin(30°)-4sin^3(30°)
1=3×1/2 - 4×1/8
1=3/2-1/2
1=2/2
1=1
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