Question

if 31 y 5 is a multiple of 3, where why is a digit, what might be the value of Y?

Answer 1

any multiple of 3 has the sum of its digits to be the multiple of 3
here when we sum its digit we will get 3+1+5+y=9+y
therefore y =0
because the sum is already the multiple of 3
hope u get it!!!
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Answer 2

We know that the digits of the multiples of 3, add up to give another multiple of 3.
For example 54 , 5+4=9 which is divisible by 3
963, 9+6+3=18 which is also divisible by 3
So they are the multiples of 3.

As per this 3+1+y+5 should be divisible by 3
Therefore y can be 0,3,6,9