Question

. If 312 is a multiple of 9, where 'z' is a digit, what is the value of z?​

Answer 1

Answer:

3

Step-by-step explanation:

z=3

Sum of all digits must be a divisible of 9 for the number divisible by 9.

Therefore,

z+3+1+2 = z+6 must be divisible by 9.

Hence, z=3