Math, asked by sujathalella, 11 months ago

if 312g is divisible by3 find the possible values of the digit g and write the possible numbers​

Answers

Answered by Anonymous
2

Answer: 0, 3, 6 and 9.

Step-by-step explanation:

Since, 312g is divisible by 3, so, 3+2+1+g is divisible by 3.

Or, 6+g is divisible by 3.

So, the possible values of g are 0, 3, 6 and 9 as,

6+0=6, which is divisible by 3.

Also, 6+3=9, which is divisible by 3.

Also, 6+6=12, which is divisible by 3.

And, 6+9=15, which is also divisible by 3.

So, the possible values of g are 0,3,6 and 9, and that is the correct answer.

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