If 31c5 is a multiple of 3, where c is a digit, then what might be the value of c?
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Answer:
c=0
Step-by-step explanation:
Divisiblity rule of 3 = sum of all numbers is equal to the multiple of 3
3+1+c+5 = 9 + c
The nearest multiple of 3 is 9 so c= 9-9
= 0
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