Math, asked by patilkrunal529, 10 hours ago

If 31c5 is a multiple of 3, where c is a digit, then what might be the value of c?​

Answers

Answered by vgehlot224
0

Answer:

c=0

Step-by-step explanation:

Divisiblity rule of 3 = sum of all numbers is equal to the multiple of 3

3+1+c+5 = 9 + c

The nearest multiple of 3 is 9 so c= 9-9

= 0

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