Question

If 31p5 is a multiple of 9,where p is a digit, find the value of p?​

Answer 1

here is ur answer:

31p5 is a multiple of 9

3 + 1 + p + 5

= 9 + p

for a multiple of 9, sum of digits must be divisible by 9.

9 + 9 = 18

p = 9

no. is 3195

hope it helps you ❤

Answer 2

Question :- If 31p5 is a multiple of 3, where p is a digit, what might be the values of p ?

Solution :-

we know that,

• if a number is a multiple of 3 , then sum of its digits is also a multiple of 3.

so,

→ 31p5 ÷ 3 = Remainder 0

or,

→ 3 + 1 + p + 5 ÷ 3 = Remainder 0

→ 9 + p ÷ 3 = Remainder 0

then, Possible values of p are :-

• if p = 0 => 9 + 0 = 9 ÷ 3 = Remainder 0 .
• if p = 1 => 9 + 1 = 10 ÷ 3 ≠ Remainder 0 .
• if p = 2 => 9 + 2 = 11 ÷ 3 ≠ Remainder 0 .
• if p = 3 => 9 + 3 = 12 ÷ 3 = Remainder 0 .
• if p = 4 => 9 + 4 = 13 ÷ 3 ≠ Remainder 0 .
• if p = 5 => 9 + 5 = 14 ÷ 3 ≠ Remainder 0 .
• if p = 6 => 9 + 6 = 15 ÷ 3 = Remainder 0 .
• if p = 7 => 9 + 7 = 16 ÷ 3 ≠ Remainder 0 .
• if p = 8 => 9 + 8 = 17 ÷ 3 ≠ Remainder 0 .
• if p = 9 => 9 + 9 = 18 ÷ 3 = Remainder 0 .

hence,

• Possible value p are = 0, 3, 6 and 9. (Ans.)

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