Math, asked by nandu7955, 19 days ago

If 31x5 is a multiple of 3, where x is a digit, what might be the value of z

Answers

Answered by rajdghadge
0

Answer:

Since 31z5 is a multiple of 3 ,the sum of its digits must be a multiple of 3 i.e. 3+1+z+5=9+z

Hence 9+z is a multiple of 3

Since z is a single digit which can value from 0 to 9

Possible values of z will be,

9+0=9

9+3=12

9+6=15

9+9=18

Thus, there can be four possible values i.e. 0,3,6 or 9

Answered by Twyla
0

Answer:

I think you have substituted the wrong variable.

31z5 is a multiple of 3 then the possible value of z are 0,3,6 or 9

if my correction is wrong then the value of z can be anything

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