If 31x5 is a multiple of 3, where x is a digit, what might be the value of z
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Answer:
Since 31z5 is a multiple of 3 ,the sum of its digits must be a multiple of 3 i.e. 3+1+z+5=9+z
Hence 9+z is a multiple of 3
Since z is a single digit which can value from 0 to 9
Possible values of z will be,
9+0=9
9+3=12
9+6=15
9+9=18
Thus, there can be four possible values i.e. 0,3,6 or 9
Answered by
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Answer:
I think you have substituted the wrong variable.
31z5 is a multiple of 3 then the possible value of z are 0,3,6 or 9
if my correction is wrong then the value of z can be anything
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