If 31z5 is a multiple of 3,where z is a digit,ehat might be the value of z??
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31z5 is a multiple of 3
So it is also divisible by 3
Using divisibility method
3+1+z+5/3
=9+z/3
= 9+3/3 ( to make divisible by 3 we need to add 3 in place of z)
Z= 3
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