if 31z5 is a multiple of 3, where z is a digit, what are the possible values that z can take
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Answer:
3,6,9
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5+1+3+z, should be a multiple of 3
=9+z Should be a mutille of 3
therefore
z=0,3,6,9
MARK BRAINLIEST.
mass32:
MARK BRAINLIEST.
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