Math, asked by garry64, 1 year ago

if 31z5 is a multiple of 3, where z is a digit, what are the possible values that z can take​

Answers

Answered by gokulnair2307
2

Answer:

3,6,9

Step-by-step explanation:

Answered by mass32
3

5+1+3+z, should be a multiple of 3

=9+z Should be a mutille of 3

therefore

z=0,3,6,9

MARK BRAINLIEST.


mass32: MARK BRAINLIEST.
mass32: PLEASE.
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