Question

if 31z5 is a multiple of 3, where z is a digit , what might be the values of z




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Answer 1

Answer:

          3 + 1 + z + 5 = 9 + z

Step-by-step explanation:

∵                     31 z5 is divisible by 3.

∴           ( 9 + z) must be divisible by 3.

i.e.        (9 + z) = 0 or 3 or 6  or 9 or 15 or 18

since,      z is a digit.

 

∴      if     9 + z = 0, then z = - 9

       if     9 + z = 3, then z = - 6

       if     9 + z = 6, then z = - 3

       if     9 + z = 9, then z = 0

       if     9 + z = 12, then z = 3

       if     9 + z = 15, then z = 6

       if     9 + z = 18, then z = 9

       if     9 + z = 21, then z = 12

       if     9 + z = 0, then z = - 9

∴    Possible values of z are 0, 3, 6 or 9.

Answer 2

Answer:

DIVISIBILTY by 3 if the sum of the number is divisible by 3 then the number is also divisible.

so z= 3,6,9