Math, asked by solankilalita1985, 4 months ago

If 31z5 is a multiple of 3,where z is a digit, what might be the values of z?​

Answers

Answered by prasanthikuchipudi
1

Answer:

3135

Step-by-step explanation:

according to divisibility rule,

if sum of digits are divisible by 3 then the number is divisible by 3

3+1+Z+5=9+z

9 divisible by 3

if we add 3 then it will be 12

12 divisible by 3

then the number is Z=3

3135 is multiple of 3

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