If 31z5 is a multiple of 3,where z is a digit, what might be the values of z?
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Answer:
3135
Step-by-step explanation:
according to divisibility rule,
if sum of digits are divisible by 3 then the number is divisible by 3
3+1+Z+5=9+z
9 divisible by 3
if we add 3 then it will be 12
12 divisible by 3
then the number is Z=3
3135 is multiple of 3
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