Math, asked by lakhwinderkaur2710, 3 days ago

If 31z5 is a multiple of 3,where z is a digit,what might be the values of z?​

Answers

Answered by saahilkumarr24
0

Answer:

0,3,6,9

Step-by-step explanation:

The addition of digits of a number should be a multiple of 3 then only it can be divisible by 3

3+1+z+5 should be equal to a multiple of 3

Answered by divasbaranwal1
0

Answer:

being a multiple of 3, the given number should be divisible by 3

divisibility rule for 3 is that the sum of all the digits should be divisible by 3

here,

3+1+z+5= 9+z

so possible values of z = 3,6,9

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