If 31z5 is a multiple of 3,where z is a digit,what might be the values of z?
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0
Answer:
0,3,6,9
Step-by-step explanation:
The addition of digits of a number should be a multiple of 3 then only it can be divisible by 3
3+1+z+5 should be equal to a multiple of 3
Answered by
0
Answer:
being a multiple of 3, the given number should be divisible by 3
divisibility rule for 3 is that the sum of all the digits should be divisible by 3
here,
3+1+z+5= 9+z
so possible values of z = 3,6,9
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