Question

If 31z5 is a multiple of 9, where z is a digit, what might be the values of z ?

Answer 1

Answer:

Given that 31z5 is a multiple of 9.

According to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.

Therefore,

3+1+z+5=9 OR 18

⇒z=9−9=0

Step-by-step explanation:

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