Question

If 3² = 27^k.9^x, find 'x' when k = 2
find I'll give you points fast​

Answer 1

Answer:

-2

Step-by-step explanation:

3² = 27^k.9^x

k=2

So, put the value of k,

3²=27²•9^x

3²/27²=(3²)^x

3²/3^6=3^2x

3^-4=3^2x

equate the power,

-4=2x

x= -4/2

x= -2