Question

If {(32^2x+1 (+ 9)} + 9 = 10, find the value of x.​

Answer 1

Answer:

$32 ^ { 2 } x+1(+9)+9=10$

$1024x+1\times 9+9=10$

$1024x+9+9=10$

$1024x+18=10$

$1024x=10-18$

$1024x=-8$

$x=\frac{-8}{1024}$

$x=-\frac{1}{128}$