If 32×577 is divisible by 3 then find the greatest value of x
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0
Answer:
577×32÷3=6154.666
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2
Answer:
32x577
the divisibility rule of 3 is sum of the digits should divisible by 3
the digits are 3,2,x,5,7,7
sum of the digits= 3+2+5+7+7+x= 24+x
24 is divisible by 3
so x can be 3,6,9
they have asked greatest value so x=9
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