Question

If 32 g of O2 contain 6.022×1023 molecules at STP then 32g of S, under the same conditions, will contain,

Answer 1

Answer:

6.023×1023 atoms because S atomic mass is 32

Answer 2

32 grams of sulfur will contain $6.022\times 10^{23} atoms$.

Explanation:

Molecules of oxygen = N = $6.022\times 10^{23} molecules$

Moles of oxygen n

$n=\frac{N}{N_A}$

$n=\frac{6.022\times 10^{23}}{6.022\times 10^{23}}=1$

So, 1 mole of oxygen gas at STP has $6.022\times 10^{23} molecules$.

Mass of sulfur = 32 g

Moles of sulfur .n'= $\frac{32g}{32 g/mol}=1 mol$

Number of sulfur atoms = N'

$N'=n'\times N_A$

$N'=1 \times 6.022\times 10^{23} atoms=6.022\times 10^{23} atoms$

32 grams of sulfur will contain $6.022\times 10^{23} atoms$.

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