Question

if 32 g of O2 contains 6.22*10^23 molecules at NTP then 32 g of S , under the same conditions , will contian

Answer 1

It will contain 6.022 x 10²³ atoms

32 gram of O₂ has 6.022 x 10²³ molecules

32 g of sulphur has 6.022 x 10²³ atoms because, 1 mole of the element weighs is 32g

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Answer 2

Answer:

6.022 x $10^{23}$

Explanation:

No of atoms = Given Mass/ Molecular Mass x 6.022 x $10^{23}$

                     Molecular Mass of S = 32g/mole

                      = 32g/32g x 6.022 x $10^{23}$

                       = 6.022 x $10^{23}$