Question

If 32 gm of O2 at 27°C is mixed with 64
gm of O2 at 327°C in an adiabatic
vessel, then the final temperature of
the mixture will be:​

Answer 1

the answer is obtained as 227°c

Answer 2

Answer:

The final temperature of  the mixture will be 227° C.

Explanation:

Given,

$T_{1}$ = 27°C

$T_{2}$ = 327°C

$m_{1}$ = 32g

$m_{2}$ = 64g

Here, Vessel is adiabatic vessel. Therefore $S_{1} = S_{2}$

Now,

$T_{f} = \frac{m_{1}T_{1} S_{1}+ m_{2}T_{2} S_{2} }{m_{1}s_{1} +m_{2}s_{2} }$

     = $\frac{32*27 + 64*327 }{32+64}$

     = $\frac{864 + 20928}{96}$

     = 227° C

Hence, the final temperature of  the mixture will be 227° C.