Question

if 32 gram of O2 contain 6.022 into 10 power 23 molecules at ntp then 32 gram of s under the same condition will content​

Answer 1

O2 contain 32 grams=6.022

1 gram contain =6.022/32=0.188*10power23*32

we get 6.016 gram

${10}^{23)$

Answer 2

32 grams of sulphur contains $6.023 \times 10^{23}$ molecules at NTP.

To find:

The no. of molecules contained in 32 grams of sulphur.

Solution:  

• Sulphur atomic number is 16 and molar mass of sulphur is 32 g/mol.

• At  NTP(Normal temperature and pressure), sulphur occupies one mole of gas which is occupies 22.4 L. Each one mole of an ideal gas contains $6.023 \times 10^{23}$ molecules.

• At NTP , 32 g/mol of sulphur gas means its equals to one moles of gas. Therefore, one mole of sulphur gas contains $6.023 \times 10^{23}$molecules at NTP .