if 3214a4 is a number divisible by 4, without leaving any remainder then the number of possible values of a is what
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Answer:
0,4,8
Step-by-step explanation:
since given no is 3214a4
here first four letters are completely divisible by 4
remaining are a4 . so now we can put values from 0 to 9 and check wheather it is divisible by 4 or not
In the end we find that only by putting 0,4 and 8
the whole no is completely divisible by 4
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