Question

if 32x 577 is divisible by 3 then find the greatest value of x​

Answer 1

The greatest value of x = 9

Given :

32x577 is divisible by 3

To find :

The greatest value of x

Concept :

Divisibility rule for 3 :

If a number is divisible by 3 if the sum of its digits is divisible by 3

Solution :

Step 1 of 2 :

Find sum of the digits

Here the given number is 32x577

Sum of the digits

= 3 + 2 + x + 5 + 7 + 7

= x + 24

Step 2 of 2 :

Find greatest value of x

Since the number 32x577 is divisible by 3

By divisibility rule of 3 , sum of the digits is divisible by 3

Consequently x + 24 is divisible by 3

⇒ x = 3 , 6 , 9

Hence the greatest value of x = 9

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Answer 2

Answer:

the greatest value of x = 9  

Step-by-step explanation:

Given data

32x577 is divisible by 3

here we need to find greatest value of x    

⇒  Divisibility rule of 3 states that if the sum of the digits in a given number is divisible by 3 then the number will also divisible by 3  

⇒  From given data   32x577 is divisible by 3

⇒  then  3+ 2+ x+ 5+ 7+ 7 should be divisible by 3

⇒  3 +2 x+ 5+ 7+ 7  = x + 24  

⇒  x + 14 will divisible by 3 for x = 0 or 3 or 6 or 9  

⇒  from above the greatest value of x = 9