Question

If 33 m of cloth is required to make 15 pants ,.How much cloth will be needed to make 25 pants?​

Answer 1

Answer:

55m .

Step-by-step explanation:

15. 25

----- = -------

33. x

Let the meters of cloth be x

(We have to cross multiply what is given )

25* 33 = 15x

825 = 15x

825/15 = x

55/ 1 = x

55 = x

Therefore 55m of cloth is required to make 25 pants.

Answer 2

Given : ↴

$\sf \: 33 \: metre \: of \: cloth \: is \: required \: to \: make \: 15 \: pants.$

To find : ↴

$\sf \: We \: have \: to \: find \: that :$

$\sf \: How \: much \: cloth \: will \: be \: needed \: to \: make \: 25 \: pants.$

So, Let's Start : ↴

$\sf \:Let \: the \: cloth\:required\: to \:make\: 25 \:pants\: be \:x.$

$\boxed{\begin{array} {c|c|c} \bf{ Number \: of } \\ { \bf{cloth}}& \sf{33 \: m}& \sf{ ? } \\ \dfrac{\qquad\qquad \qquad}{} & \dfrac{\qquad}{} & \dfrac{\qquad}{} \\ \bf{Pants} & \sf{15}& \sf{25} \\ \dfrac{\qquad \qquad\qquad}{} & \dfrac{\qquad}{}& \dfrac{\qquad}{} \end{array}}$

This is a condition of Direct variation.

Direct variation means when one quantity changes, the other quantity also changes in direct proportion.

$\sf \boxed { \sf33 \: \times \: 25 \: = \: 15 \: \times \: x}$

$\sf \longrightarrow \: \cfrac{33 \: \times \: 25}{15}$

$\sf \: \longrightarrow \: \cfrac{33 \: \times \: \not{2 \not5}}{ \not1 \not5} \: = \: \cfrac{33 \: \times \: 5}{ 3} \:$

$\longrightarrow \: \cfrac{ \not3 \not3 \: \times 5}{ \not3} \: = \sf11 \times 5$

$\sf \longrightarrow \: 11 \: \times \: 5 \: = \: 55$

So, Hence 55 metre of cloth is required to make 25 pants.

$\sf \: \longrightarrow \: Answer : \: 55 \: metre.$