Question

If 340g of mixture of n2 and h2 in correct ratio give a 20% yield of nh3 produced mass of nh3 is

Answer 1

Consider the reaction:

N₂ + 3H₂---->2NH₃

At NTP,

34 g of reaction mixture expected to give=34 g of NH₃

340 g of reaction mixture expected to give=340 g of NH₃

$yield = \frac{obtained product mass\times 100}{Expected product mass}$

$20 = \frac{obtained product mass\times 100}{340}$

obtained product mass that is NH₃ formed=

$\frac{20\times 340}{100}$

obtained product mass that is NH₃ formed= 68 g