Question

If 340g of mixture of n2 and h2 in the correct ratio gave a 20% yeild of nh3 the product mass of nh3 would be

Answer 1

Consider the reaction:

N₂ + 3H₂---->2NH₃

At NTP,

34 g of reaction mixture expected to give=34 g of NH₃

340 g of reaction mixture expected to give=340 g of NH₃

$yield percent= \frac{obtained product mass that is NH_{3}formed\times 100}{expected product mass that is NH_{3}formed}$

$20= \frac{obtained product mass that is NH_{3}formed\times 100}{340}$

obtained product mass that is NH₃ formed=$= \frac{20\times 340}{100}$

obtained product mass that is NH₃ formed= 68 g

Answer 2

Consider the reaction:

N₂ + 3H₂---->2NH₃

At NTP,

34 g of reaction mixture expected to give=34 g of NH₃

340 g of reaction mixture expected to give=340 g of NH₃

obtained product mass that is NH₃ formed=

obtained product mass that is NH₃ formed= 68 g

Read more on Brainly.in - https://brainly.in/question/5274078#readmore

Consider the reaction:

N₂ + 3H₂---->2NH₃

At NTP,

34 g of reaction mixture expected to give=34 g of NH₃

340 g of reaction mixture expected to give=340 g of NH₃

obtained product mass that is NH₃ formed=

obtained product mass that is NH₃ formed= 68 g

Read more on Brainly.in - https://brainly.in/question/5274078#readmore