Question

If 342 gram of sucrose present in 10 liter solution find the molarity of the

solution​

Answer 1

Answer:

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>>Colligative Properties and Determination of Molar Mass

>>A solution of sucrose (molar mass = 342

Question

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A solution of sucrose (molar mass = 342 g mol

−1

) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be:

[K

f

for water =1.86 K kg mol

−1

]

Medium

Solution

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Correct option is A)

DepressioninFreezingpointΔT

f

=

M

1

×W

2

W

1

×K

f

×1000

whereW

1

=Weight of Solute

W

2

=Weight of solvent

M

1

=Molar mass of solute

K

f

=Freezing point deprssion constant

Now,ΔT

f

=

342×1000

1.86×68.5×1000

=0.372C

Now,ΔT

f

=T

o

−T

f

So,T

f

=0−0.372=−0.372C.

(Freezing point of purewater=0

0

C.)