if 35Cn+7=35C4n-2, then n =?
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Given
35
C
n+7
=
35
C
4n−2
It is in form if
n
C
x
=
n
C
v
, then
x=y or x+y=n
now
(i)
n+7=4n-2
4n-n=7+2
3n=9
n=3
(ii)
n+7+4n-2=35
5n+5=35
5n=30
n=6
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