If 36 gm of NaCl is dissolved in 100 gm of water, find it`s concentration at room temperature
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Answered by
1
hey!!
molality= no of moles of solute /weight of solvent in kg
no of moles=given mass/gram molecular mass
no of moles=36/58
no of moles=0.6
weight of solvent=0.1 kg
molality=0.6/0.1
molality=6 molal
hope it helps u
molality= no of moles of solute /weight of solvent in kg
no of moles=given mass/gram molecular mass
no of moles=36/58
no of moles=0.6
weight of solvent=0.1 kg
molality=0.6/0.1
molality=6 molal
hope it helps u
Answered by
1
molality=no. of moles of solute/wt. of solvent(in kg. )
=36/58.5 = moles of NaCl
,100gm w. of solvant
= 0.615m
=36/58.5 = moles of NaCl
,100gm w. of solvant
= 0.615m
Anonymous:
hey u have to change weight of solvent in kg
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