Question

if 360g of urea is dissolved in 1000g of water. find the molarity of solution if density is 1.12g/mol.​

Answer 1

Answer:

0.5

Explanation:

mass of solute(urea) = 360g

mass of solvent(water) = 1000g

Molarity = n/V

n = number of moles of solute = mass given / molar mass

= 360/60 = 6

density of solution is 1.12g/mol

m(soln.) = m(solute) + m(solvent)

density(soln.) × V(soln.) = 360 + 1000

1.12 × Vol(soln.) = 1360

V(soln.) = 1360/1.12 = 1214.28 ml = 1.21 L

M = n/ V

= 6/ 1.21

= 0.49 ~ 0.5