Math, asked by SHIVAMDHASMANA, 2 months ago

If 36a2 - b = (6a + 1/15) (6a - 1/15), then the value of b is

Bekar... wbu ?​

Answers

Answered by MissVirius
5

Step-by-step explanation:

Given is 3a+(1/2a)=9(equation1) . Hence, we are required to find 2a+(1/3a)=?(equation2) .

If we solve this, equation 1 becomes (6a2+1)/2a=9 , which after further simplification becomes 6a2+1=18a(equation3) .

Simplifying equation 2 we get: (6a2+1)/3a=x (we need to find x)

Further simplifying equation 2, we get; 6a2+1=(3a)x(equation4)

Substituting equation 3 in equation 4, we get 18a=(3a)x which when solved is x=18a/3a , x=6 .

Therefore, answer is 6.

Me tujh SE bhi jayada bekar :(

Answered by allamraju792
1

Step-by-step explanation:

36a2-b=(6a+1/15)(6a-1/15)

36a2-b=(2+1/5)(2+1/5)

36a2-b=4a/5-4a/5

36a2-b=3a/5-1a/5

36a2-b=2a/5

2a+2/5-b=36a

4a-b/5=36a

4ab/5=36a

4ab=36a×5

4b=180

b=180/4

b=45

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