Question

If 36a2 - b = (6a + 1/15) (6a - 1/15), then the value of b is

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Answer 1

Answer:

p {(x)} = x ^ {2} - 2 \sqrt{2} x + 1 }\\ { \text{Solve for } q \text{ where} } \\ { q = p {(2 \sqrt{2the multiplicative inverse of 10square 5 is=The required value is 3.

Step-by-step explanation:

Given :

9, a, b and -6 are in A.P

To find :

the value of (a + b)

Solution :

In an A.P, the difference between the term and it's preceding term is constant.

So,

a - 9 = b - a = -6 - b

⇒ a - 9 = -6 - b

⇒ a = -6 - b + 9

⇒ a = 3 - b

⇒ a + b = 3

∴ The value of (a + b) is 3

_____________________________

Arithmetic Progression :

It is the sequence of numbers such that the difference between any two successive numbers is constant.

In AP,

a - first term

d - common difference

aₙ - nth term

Sₙ - sum of n terms

General form of AP,

a , a+d , a+2d , a+3d , ...

nth term of AP,

aₙ = a + (n - 1)d

Sum of first n terms in A.P,

\longmapsto \sf S_n=\dfrac{n}{2}[2a+(n-1)d]⟼S

n

=

2

n

[2a+(n−1)d]