Question

If 376 x 5 is a multiple of 3, where x is a digit, what is the highest value of x ?​

Answer 1

Answer:

x=0,3,6or9.It's upon your wish.

Answer 2

$Given \: number \: 376x5$

$Sum \: of \: the \: digits \\= 3+7+6+x+5 \\= 21+x$

$If \: value \: of \: x \:is \: 0,3,6\:or 9 \: then \\the \: given \: number \: should \: be \: multiple \:of \:3$

/* But according to the problem , x must be highest value */

Therefore.,

$\red{ Value \: of \: x \: } \green { = 9 }$

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