Math, asked by anilprajapati7600, 10 months ago

If 378 coins consist of 1 rupee, 50 paise and 25 paise coins, whose values are in the ratio of 13 : 11 7. The number of 50 paise coins will be:

Answers

Answered by Anonymous
4

Total coins = 378

Ratio of values = 13 : 11 : 7

In 1 rupee, no. of rs. 1 coins = 1

In 1 rupee no. of 50 P coins = 2

In 1 rupee, no. of 25 P coins = 4

Ratio of Rs. 1, 50 P, 25 P coins = 13 * 1 : 11 * 2 : 7 * 4

                                                   = 13 : 22 : 28

Now,

Number of 50 p coins = (22/13 + 22 + 28) * 378

                                     = (22/63) * 378

                                     = 132

Answered by Anonymous
2

Let:-

Numbers of coins of 1 rupees, 50 paise and 25 paise are 13x, 11x and 7x respectively.

Then:-

Numbers of coins will be as

➤ 13x * 1 = 13x

➤ 11x * 2 = 22x

➤ 7x * 4 = 28x

Total = 63x

According to Question:-

➤ 63x = 378

➤ x = 378/63

➤ x = 6

Therefore:-

No. of 1 rupees coins, 13x = 6*1 = 6

No. of 50 paise coins, 22x = 22*6 = 132

No. of 25 paise coins, 28x = 28*6 = 168

Hence:-

Required answer is 132.

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