Math, asked by adhaliwal4873, 1 year ago

If 378 coins consist of rupee, 50 paise and 25 paise coins, whose values are proportional to 13 :11 : 7, the number of 50 paise coins will be

Answers

Answered by shameemamk
5
Please find the attached answer
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Answered by Anonymous
0

Answer:-

  • Required answer is 132.

Let:-

Numbers of coins of 1 rupees, 50 paise and 25 paise are 13x, 11x and 7x respectively.

Then:-

Numbers of coins will be as

➤ 13x * 1 = 13x

➤ 11x * 2 = 22x

➤ 7x * 4 = 28x

  • Total = 63x

According to Question:-

➤ 63x = 378

➤ x = 378/63

➤ x = 6

Therefore:-

No. of 1 rupees coins, 13x = 6*1 = 6

No. of 50 paise coins, 22x = 22*6 = 132

No. of 25 paise coins, 28x = 28*6 = 168

Hence:-

Required answer is 132.

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