Question

If 38.5 g of CCl4 combines completely with xg of SbF3 according to the following reaction CCl4 + SbF3 → CCIF3 + SbC13 Then the value of xis [Molar mass of SbF3 is 179 gmol-1 and CCIA is 154 gmol-']​

Answer 1

Answer:

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Explanation:

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Answer 2

The amount of carbon remaining unreacted reaction is 26.5 g.

Explanation:

The balanced chemical reaction is $C+2Cl_{2}$ → $CCl_{4}$.

38.5 g of carbon will react with $\frac{38.5}{12} *2*71=455.5g$ of chlorine.

however, only 179 g of chlorine is present.

Thus chlorine is the limiting reagent

$179 g of chlorine will produce \frac{179*154}{71*2}=776.5g of carbon tetrachloride$

$179g$ of(2 moles) chlorine of will react with 12 g(1 mole)of carbon.

The amount of carbon remaining unreacted after the reaction is 38.5-12=26.5 g.