Question

If (3a + 1)^2 + (b − 1)^2 + (2c − 3)^3 = 0, then the value of (3a+b+2c) is equal to:​

Answer 1

Answer:

3

Step-by-step explanation:

(3a+1)²+(b-1)²+(2c-3)³=0

let  (3a+1)²=0

3a=-1

a=-1/3

let (b-1)²=0

b=1

(2c-3)³=0

c=3/2

a=-1/2;b=1;c=3/2

3a+b+2c=3(-1/3)+1+2(3/2)

              = -1+1+3

3a+b+2c =3