if 3a + 1/3a=2√3
evaluate: 81a4+1/81a4
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Answered by
1
Answer:
98
Step-by-step explanation:
The expansion of the identity (x+1/x)⁴ goes
x⁴+1/x⁴+4(x²+1/x²)+6
To find:- 9a²+1/9a²
(3a+1/3a)²=9a²+1/9a²+2
(2√3)²=9a²+1/9a²+2
hence, 9a²+1/9a²=12-2 [ Transposing ]
= 10
Therefore,
LHS= (3a+1/3a)⁴
RHS
= (3a)⁴+1/(3a)⁴+4(3a)²+1/(3a)²+6
(2√3)⁴ = 81a⁴+1/81a⁴+4(9a²+1/9a²)+6
144= 81a⁴+1/81a⁴+4(10)+6
81a⁴+1/81a⁴= 144-46. [ Transposing ]
= 98
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