Question

IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​

Answer 1

Answer:IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​IF 3a+2b + 4c=26 and 6b+4a+2c=48 then a+b+c =?​

Step-by-step explanation:

Answer 2

3a + 2b +4c =26 and 6b + 4a +2c= 48

Divide the second equation by 2,

3b+2a+c=24

Add this to first equation

5a+5b+5c=50

a+b+c=10