Question

if(3a+2b):(5a+3b)=18:29......find a:b

Answer 1

$\frac{(3a + 2b)}{5a + 3b} = \frac{18}{29} \\ 29(3a + 2b) = 18(5a + 3b) \\ 87a + 58b = 90a + 54b \\ 58b - 54b = 90a - 87a \\ 4b = 3a \\ \frac{b}{a} = \frac{3}{4} \\ \frac{a}{b} = \frac{4}{ 3} \\ a = 4 \: and \: b = 3$

Answer 2

Answer:

a:b is equals to 4:3

Step-by-step explanation:

Given (3a+2b):(5a+3b)=18:29

We have to find a:b

$\frac{3a+2b}{5a+3b}=\frac{18}{29}\\\\29(3a+2b)=18(5a+3b)\\\\87a+58b=90a+54b\\\\4b=3a\\\\\frac{4}{3}=\frac{a}{b}$

hence, a:b is equals to 4:3