Math, asked by lalita2397, 11 months ago

If 3a+2b=5c and abc=0 find the value of 27a3+8b3-125c3

Answers

Answered by basilvictor
8

Answer:

0

Step-by-step explanation:

27a³ + 8b³ - 125c³ = (3a)³ + (2b)³ + (-5c)³

Now,

3a + 2b = 5c

or, 3a + 2b - 5c = 0

Therefore,

(3a)³ + (2b)³ + (-5c)³ = 3(3a)(2b)(-5c)

= -90abc = 0

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