If 3a+2b=5c and abc=0 find the value of 27a3+8b3-125c3
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Answer:
0
Step-by-step explanation:
27a³ + 8b³ - 125c³ = (3a)³ + (2b)³ + (-5c)³
Now,
3a + 2b = 5c
or, 3a + 2b - 5c = 0
Therefore,
(3a)³ + (2b)³ + (-5c)³ = 3(3a)(2b)(-5c)
= -90abc = 0
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