History, asked by UserBusy, 11 months ago

If 3a+2b=5c and abc=4.
Find the value of :
27 {a}^{3}  + 8 {b}^{3}  - 125 {c}^{3}

Answers

Answered by aishwaryashree3
0

27a³ + 8b³ - 125c³= (3a)³+ (2b)³ + (-5c)³

3a + 2b = 5c

3a + 2b - 5c = 0

Hence, (3a)³ + (2b)^3 + (-5c)³ = 3 (3a) (2b)(-5c)

= -90 abc = -90 x 0 = 0.ans...

hope this will help

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Answered by Anonymous
0

27a³ + 8b³ - 125c³= (3a)³+ (2b)³ + (-5c)³

3a + 2b = 5c

3a + 2b - 5c = 0

Hence, (3a)³ + (2b)^3 + (-5c)³ = 3 (3a) (2b)(-5c)

= -90 abc = -90 x 0 = 0.ans...

hope this will help


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