Question

If 3A=2B=5C,then find A:B:C

Answer 1

let 
3A = 2B = 5C =K

then 3A = K⇒ A = K/3
        2B =K ⇒B= K/2
        5C = K ⇒C = K/5

therefore
 A:B:C = K/3 : K/2 : K/5
DIVIDE each term with 30/K

A:B:C = 30K/3K  : 30K/2K  : 30K/5
          = 10 : 15 : 6
A :B : C =10:15:6